已知z9=1(z∈C,z≠1),θ是z的辐角. 证明: 1+z+z2+z3+z4+z5+z6+z7+z8=0;

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问题 已知z9=1(z∈C,z≠1),θ是z的辐角.
证明:
1+z+z2+z3+z4+z5+z6+z7+z8=0;

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答案z(1+z+z2+z3+z4+z5+z6+z7+z8) =z+z2+z3+z4+z5+z6+z7+z8+z9 =z+z2+z3+z4+z5+z6+z7+z8+1 移项得,(z一1)(1+z+z2+z3+z4+z5+z6+z7+z8)=0, 又因为z≠1,故1+z+z2+z3+z4+z5+z6+z7+z8=0.

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