设 (Ⅰ)证明:A~B; (Ⅱ)求可逆矩阵P,使得P-1AP=B.

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问题
(Ⅰ)证明:A~B;
(Ⅱ)求可逆矩阵P,使得P-1AP=B.

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答案[*] 由P2-1BP2=P1-1AP1得B=P2P1-1AP1P2-1(P1P2-1)-1AP1P2-1, [*]

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