首页
外语
计算机
考研
公务员
职业资格
财经
工程
司法
医学
专升本
自考
实用职业技能
登录
外语
Patricia purchased x meters of fencing. She originally intended to use all of the fencing to enclose a square region, but later
Patricia purchased x meters of fencing. She originally intended to use all of the fencing to enclose a square region, but later
admin
2022-10-18
67
问题
Patricia purchased x meters of fencing. She originally intended to use all of the fencing to enclose a square region, but later decided to use all of the fencing to enclose a rectangular region with length y meters greater than its width. In square meters, what is the positive difference between the area of the square region and the area of the rectangular region?
(1) xy=256
(2) y = 4
选项
A、Statement (1) ALONE is sufficient, but statement (2) alone is not sufficient.
B、Statement (2) ALONE is sufficient, but statement (1) alone is not sufficient.
C、BOTH statements TOGETHER are sufficient, but NEITHER statement ALONE is sufficient.
D、EACH statement ALONE is sufficient.
E、Statements (1) and (2) TOGETHER are NOT sufficient.
答案
B
解析
The square’s perimeter is x meters, and thus the square has adjacent sides of length x/4 meters each. Since the rectangle’s perimeter is also x meters, with adjacent side lengths that differ by y meters, it follows that the rectangle’s length is (x/4+y/2) meters (i.e., lengthen two opposite sides of the square by y/2 meters) and the rectangle’s (x/4+y/2) meters (i.e., shorten the two other opposite sides of the square by y/2 meters).
Alternatively, letting L and W be the length and width, respectively and in meters, of the rectangle, then we can express each of L and Win terms of x and y by algebraically eliminating L and W from the equations 2L + 2W= x and L = W+y.
2L + 2W = x given
2(W+y) + 2W = x substitute
L=W+y
W=x/4+y/2 solve for W
L = x/4 + y/2 use L = W+ y
Therefore, in square meters, the area of the square is (x/4) , the area of the rectangle is(x/4+y/2)(x/4-y/2)=(x/4)
2
-(y/2)
2
, and the positive difference between these two areas is(y/2).
Determine the value of(y/2).
(1) Given xy = 256, it is clearly not possible to determine the value of (y/2)
2
;NOT sufficient.
(2) Given y = 4, the value of (y/2)
2
is equal to 4; SUFFICIENT.
The correct answer is B;
statement 2 alone is sufficient.
转载请注明原文地址:https://kaotiyun.com/show/fttO777K
本试题收录于:
GMAT QUANTITATIVE题库GMAT分类
0
GMAT QUANTITATIVE
GMAT
相关试题推荐
Onetypeofpersonthatiscommoninmanycountriesistheonewhoalwaystriestodoaslittleaspossibleandtogetasmuchi
SHANGHAI:【T1】Eligible(符合条件的)couplesinthecityareforthefirsttimebeingencouragedtohaveasecondchild,asauthoritiesm
Tom______theshopkeeperwithovercharginghimforthearticleshehadbought.
Nomatterwhoyouareorwhereyoucomefrom,onethingiscertain:youareacquaintedwiththemosquito(蚊子)—althoughyouprobab
Inanoldtownlivedamerchant.Heearnedhugeprofitsbyfairmeansandfoul(恶劣的).Withmoreprofitsflowingin,hebecamemor
Allthefollowingcasesareon-the-jobsmokingexceptthat______.Passivesmokingmeans______.
Youmusthavebeentroubledbywhentosay"Iloveyou"becauseitisoneofthegreatestpuzzlesinourlife.Whatifyous
Solvetheproblemandindicatethebestoftheanswerchoicesgiven.NUMBERS:Allnumbersusedarerealnumbers.FIGURES:
Today’slowgasolinepricesmakeconsumerswillingtoindulgetheirpreferenceforlargercars,whichconsumegreateramountsof
Anthropologywasmuchmorethan______forthenovelistZoraNealeHurston:shestudiedatBarnardCollegewithFranzBoas,whoi
随机试题
从塑造形象的角度揭示公共关系的本质属性的是()
以下关于心室肌相对不应期的描述,正确的是()。
钙通道阻断药物不能用于治疗下列哪种疾病:
肠蛔虫堵塞的临床特点是
A.妇女型骨盆B.均小型骨盆C.扁平型骨盆D.男子型骨盆E.类人猿型骨盆入口横椭圆形,前后径变短,横径较长,中骨盆平面宽大的是
X线表现为根间周圆形透射区,边缘有致密线环绕的病变是
电讯检疫必须是持有效的( )国际航行船舶在抵港前24小时,通过船舶公司或船舶代理向港口或锚地所在地检验检疫机构以电报形式报告。
妈妈为了给过生日的小东一个惊喜,在一底面半径为20cm、高为60cm的圆锥形生日帽内藏了一个圆柱形礼物盒。为了不让小东事先发现礼物盒,该礼物盒的侧面积最大为多少?
一、注意事项1.申论考试是对应试者阅读理解能力、综合分析能力、提出和解决问题能力和文字表达能力进行考查的考试。2.作答参考时限:阅读材料40分钟,答卷110分钟。3.仔细阅读给定资料,按照后面提出的申论要求依次作答。二、给定资料
Hesaidnothing,leavingme____________(对他的计划毫不知情)
最新回复
(
0
)