The figure shows the graph of the equation y = k-x2, where k is a constant. If the area of triangle ABC is 1/8, what is the valu

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问题
The figure shows the graph of the equation y = k-x2, where k is a constant. If the area of triangle ABC is 1/8, what is the value of k? Give your answer to the nearest 0.01.

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答案0.25

解析 根据二次函数Y=k-x2,求出A、B、C三点坐标。令x=0,得Y=k,则A点坐标(0,k),|OA|=k令y=0,得x=,则B点坐标(,0),C点坐标(,0),|BC|=。所以三角形面积为;=1/8→k=1/4=0.25。
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