The celebration of the New Year is the oldest one of all holidays. It was first【C1】______in【C2】______Babylon about 4,000 years a

admin2019-04-19  45

问题    The celebration of the New Year is the oldest one of all holidays. It was first【C1】______in【C2】______Babylon about 4,000 years ago. New Year’s Day is an【C3】______national holiday, and banks and offices will be closed. Many families have New Year’s Day【C4】______.
   Traditionally, it was thought that it could【C5】______the luck they would have【C6】______the coming year by【C7】______they did or ate on the first day of the year. For that reason, it has become common for【C8】______to celebrate the first few minutes of a【C9】______new year in the【C10】______with the family and friends. Parties often last into the middle of the night after the ringing of a new year. It was once believed that the first visitor on New Year’s Day would bring【C11】______good luck or bad luck to the rest of the year. It was particularly lucky if that visitor【C12】______to be a tall dark-haired man.
   Traditional New Year’s【C13】______are also thought to bring luck. People in many parts of the US celebrate the New Year by【C14】______black-eyed peas and cabbage. Black-eyed peas have been considered good luck in many cultures. Cabbage leaves are considered a【C15】______of prosperity, being【C16】______of paper currency. Other traditions of the season include the making of New Year’s resolutions. That tradition also【C17】______back to the early Babylonians. Popular modern resolutions might include the【C18】______to lose weight or quit smoking.
   The song, " Auld Lang Syne" , is sung at the【C19】______of midnight in almost every English-speaking country in the world to bring in the New Year. " Auld Lang Syne" literally【C20】______"yearning for the old days."
【C18】

选项 A、pronunciation
B、revenge
C、review
D、promise

答案D

解析 本题考查点是语境推断。本题全篇内容是讨论“新年”;本题空白处前后的词语“resolutions(决心)”和“to lose weight or quit smoking(减肥或者戒烟)”提示本题应该选用D(promise诺言;保证),因为这样才能保持本句语意上的通顺一致。
转载请注明原文地址:https://kaotiyun.com/show/z76Z777K
0

最新回复(0)