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The average ( arithmetic mean) of 3 different positive integers is equal to the average of 5、7、8、9 and 11. Column A
The average ( arithmetic mean) of 3 different positive integers is equal to the average of 5、7、8、9 and 11. Column A
admin
2009-05-19
110
问题
The average ( arithmetic mean) of 3 different positive integers is equal to the average of 5、7、8、9 and 11.
Column A Column B
The greatest possible value of the greatest 21
of the 3 different integers
选项
A、if the quantity in Column A is greater
B、if the quantity in Column B is greater
C、if the two quantity are equal
D、if the relationship cannot be determined from the information given
答案
C
解析
三个不同正整数的算术平均值等于5、7、8、9和11的平均值。
解:本题的正确答案为(C)。比较的左项为3个不同正整数中最大数的最大可能值。5、7、8、9和11平均值是8,故3个正整数的和为3×8=24.因此当另外两数分别为1和2时,3个不同正整数中最大数的最大可能值是21。
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