2. 考研
  3. cos(sinx)=1-sin2x/2!+sin4x/4!+o(x4)sin2x=[x-x3/3!+o(x3)]2=x2-x4/3+o(x4)，sin4x=[x-x3/3!+o(x3)]4=x4+o(x4)，cos(sinx)=1-1/2x2+5x4/24

cos(sinx)=1-sin2x/2!+sin4x/4!+o(x4)sin2x=[x-x3/3!+o(x3)]2=x2-x4/3+o(x4)，sin4x=[x-x3/3!+o(x3)]4=x4+o(x4)，cos(sinx)=1-1/2x2+5x4/24

admin2022-03-31  31
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答案cos(sinx)=1-sin2x/2!+sin4x/4!+o(x4)sin2x=[x-x3/3!+o(x3)]2=x2-x4/3+o(x4)，sin4x=[x-x3/3!+o(x3)]4=x4+o(x4)，cos(sinx)=1-1/2x2+5x4/24+o(x4)，cosx=1-1/2x2+x4/24+o(x4)，则cos(sinx)-cosx～1/6x4， [*]
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考研数学三

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