What is the equation of a line perpendicular to 3x = 2 - y with the y-intercept 8?

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问题 What is the equation of a line perpendicular to 3x = 2 - y with the y-intercept 8?

选项

答案y =[*]+ 8

解析 First, rearrange the equation into slope-intercept form, by subtracting 3x and -y from both sides:
y = -3x+ 2
For two lines to be perpendicular, their slopes must be negative reciprocals. The negative reciprocal of -3 is 1/3. The problem also states that the perpendicular line has a y-intercept of 8. If you substitute 1/3 for m and 8 for b in the standard equation, you get y =

+ 8.

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What is the equation of a line perpendicular to 3x = 2 - y with the y-intercept 8?

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