证明: (Ⅰ)∫0π/2lnsinxdx=∫0π/2lncosxdx; (Ⅱ)∫0π/2lnsin2xdx=∫0π/2lnsinxdx; (Ⅲ)∫0π/2lnsinxdx=-ln2.

admin2018-06-15  22

问题 证明:
(Ⅰ)∫0π/2lnsinxdx=∫0π/2lncosxdx;
(Ⅱ)∫0π/2lnsin2xdx=∫0π/2lnsinxdx;
(Ⅲ)∫0π/2lnsinxdx=-ln2.

选项

答案[*] (Ⅲ)由题(Ⅱ)与题(Ⅰ)得 [*]

解析
转载请注明原文地址:https://kaotiyun.com/show/6Dg4777K
0

最新回复(0)