2. 外语
  3. n/4+r/8=s/5+t/10 n, r, s and t are positive integers Quantity A: 2n+r Quantity B: 2s+t

n/4+r/8=s/5+t/10 n, r, s and t are positive integers Quantity A: 2n+r Quantity B: 2s+t

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问题 n/4+r/8=s/5+t/10
n, r, s and t are positive integers
Quantity A: 2n+r
Quantity B: 2s+t
选项 A、Quantity A is greater.
B、Quantity B is greater.
C、The two quantities are equal.
D、The relationship cannot be determined from the information given.
答案B
解析 设n/4+r/8=s/5+t/10=m，那么2n+r=8m，2s+t=10m，由于n，r，s，t都是正整数，因此m也是正整数，所以答案为B。
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