首页
外语
计算机
考研
公务员
职业资格
财经
工程
司法
医学
专升本
自考
实用职业技能
登录
外语
Huiyuan Service Apartment Located in the Asian Games Village, with a 10,000m2 central garden and a children’s playground. Eig
Huiyuan Service Apartment Located in the Asian Games Village, with a 10,000m2 central garden and a children’s playground. Eig
admin
2009-05-28
75
问题
Huiyuan Service Apartment
Located in the Asian Games Village, with a 10,000m2 central garden and a children’s playground. Eight different styles of buildings with 1,000 apartments ranging from one-bedroom-one-sitting room to four-bedroom-two-sitting ro
选项
答案
Hotel-style
解析
转载请注明原文地址:https://kaotiyun.com/show/OkwK777K
本试题收录于:
大学英语三级B级题库大学英语三级分类
0
大学英语三级B级
大学英语三级
相关试题推荐
Whydidthemansaythatpeopleinhispicturemightbefromthe19thcentury?
Inthissection,youwillhearashortpassage.Forquestions21—30,completethenotesusingnomorethanthreewardsforeach
MyfriendTanya______Japaneseforsixyearsbeforeshe______Japan.I’vejustreceivedaletterfromher.Itsaysshehasbee
Becausestereotypesarestandardizedand______ideasofgroups,basedonsomeprejudices,theyarenotderived______objectivefac
______forthetimelyinvestmentfromthegeneralpublic,ourcompanywouldn’tbesothrivingasitis.
Inthepast,mostcitiesusuallywerethenaturaloutgrowthofvillagesandtownsthathappenedtoprosper.Romestartedoutas
It’s4.45a.m.inSamasativillageinnorth-westernZambiaandtheChimwangafamily,championbeekeepers,arealreadyontheir
ShanxiprovincenurturesanancientcivilizationinthemidsectionoftheYellowRiver,withpicturesquenaturalsceneryandcul
DavidCameronhaspledgedtherewillbe"nolimit"tothenumberofstudentsfromIndiawhocanstudyintheUKandthenstayo
Acommoncomplaintforpeopleeachyeariscatchingacold.Manyuncomfortablesymptomsaccompanyacold.Eachyear,coldsuffer
随机试题
下列《论毅力》中的论据,强调只有毅力至强方能取得事业最终成功的有
属于骨折的早期并发症是
治疗小儿紫癜属血热妄行型的首选方剂是
裂化是指有机化合物在高温下分子发生分解的反应过程,分为热裂化、催化裂化、加氢裂化。热裂化存在的主要危险性是()。
属于居住区主要道路的布置形式的是()。
自动控制系统中,一般都采用方框图来表示其系统的组成,方框图中除有基本符号方块外,还有( )。
按照相关消防设计规范要求对建筑物进行灭火器配置验收,下列灭火器配置验收合格的是()。
未按中国人民银行统一规定印制的票据是无效票据,不能作为支付结算的凭证。()
人力资源供求预测的主要目的是估计未来某个时期企业对()的需求,这是人力资源规划中较具技术性的关键部分。
求函数f(x)=(2-t)e-tdt的最大值与最小值.
最新回复
(
0
)