求∫arctanex/exdx.

admin2022-10-12  21

问题 求∫arctanex/exdx.

选项

答案令ex=t,dx=1/tdt,∫arctanex/exdx=∫arctant/t2dt=-∫arctantd(1/t)=-arctant/t+∫1/t(1+t2)dt=-arctant/t+∫(1/t-t/(1+t2))dt=-arctant/t+lnt-1/2ln(1+t2)+C=-arctanex/ex+x-1/2ln(1+e2x)+C.

解析
转载请注明原文地址:https://kaotiyun.com/show/OsC4777K
0

最新回复(0)