设f(x,y)=f(x,y)dxdy. 其中D={(x,y)|a≤x+y≤b)(0<a<b).

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问题 设f(x,y)=f(x,y)dxdy.
其中D={(x,y)|a≤x+y≤b)(0<a<b).

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答案令D1={(x,y)|0≤x≤a,a-x≤y≤b-x}, D2={(x,y)|a≤x≤b,0≤y≤b-x},则 [*]f(x,y)dxdy=∫0ae-xdx∫a-xb-xe-ydy+∫abe-xdx∫0b-x e-ydy =∫0aee-x(ex-a-ex-b)dx+∫abe-x(1-ex-b)dx =(a+1)(e-a-e-b)-(b-a)e-b

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