∫-π/2π/2(cosx/(2+sinx)+x2sinx)dx．

admin2022-10-25 49

问题 ∫_-π/2^π/2(cosx/(2+sinx)+x²sinx)dx．

选项

答案∫_-π/2^π/2(cosx/(2+sinx)+x²sinx)dx=∫_-π/2^π/2cosx/(2+sinx)dx=∫_-π/2^π/2d(2+sinx)/(2+sinx)=ln(1+sinx)｜_-π/2^π/2=ln3．

解析

转载请注明原文地址:https://kaotiyun.com/show/PIC4777K

考研数学三

相关试题推荐

随机试题

最新回复(0)