求下列函数的导数: y=(x2+1)(3x-1)(1-x3);

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问题 求下列函数的导数:
y=(x2+1)(3x-1)(1-x3);

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答案y’=(x2+1)’(3x-1)(1-x3)+(x2+1)(3x-1)’(1-x3)+(x2+1)(3x-1)(1-x3)’ =2x(3x-1)(1-x3)+(x2+1)·3(1-x3)+(x2+1)(3x-1)(-3x2) =-18x5+5x4-12x3+12x2-2x+3.

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