设函数y=y(x)由e2x+y—cos(xy)=e一1确定,则曲线y=y(x)在x=0对应点处的法线方程为_________.

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问题 设函数y=y(x)由e2x+y—cos(xy)=e一1确定,则曲线y=y(x)在x=0对应点处的法线方程为_________.

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答案y=[*]x+1

解析 当x=0时,y=1,e2x+y一cos(xy)=e一1两边对x求导得e2x+y(2+)+sin(xy)(y+)=0,将x=0,y=1代入得=一2,故所求法线方程为y一1=(x一0),即y=x+1.
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