设f(x)在[-π,π]上满足f(x+π)=-f(x),则f(x)的傅里叶级数的系数a2n=________(n为正整数).

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问题 设f(x)在[-π,π]上满足f(x+π)=-f(x),则f(x)的傅里叶级数的系数a2n=________(n为正整数).

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答案0.

解析 由于
    a2n=πf(x)cos 2nxdx=[∫0f(x)cos 2nxdx+∫0πf(x)cos 2nxdx],
    且
    ∫0πf(x)cos 2nxdx0f(t+π)cos 2n(t+π)dt
    =∫0f(x+π)cos 2nxdx,
    故
    a2n=0[f(x)+f(x+π)]cos 2nxdx=0.
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