设函数z=f(x,y)(xy≠0)满足则dz=__________.

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问题 设函数z=f(x,y)(xy≠0)满足则dz=__________.

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答案(2x-y)dx-xdy

解析,有即f(x,y)=x2一xy.所以dz=(2x-y)dx-xdy.
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