设f’(x)在[a,b]有连续的导数,求证:

admin2017-05-31  25

问题 设f’(x)在[a,b]有连续的导数,求证:

选项

答案可设[*]=|f(x0)|,即证 (b-a)|f(x0)|≤|∫abf(x)dx|+(b-a)∫ab|f’(x)|dx, 即证 |∫abf(x0)dx|-|∫abf(x)dx|≤(b-a)∫ab|f’(x)|dx. 注意 |∫abf(x0)dx|-|∫abf(x)dx|≤|∫ab[f(x0)-f(x)]dx| =[*]≤∫ab[∫ab|f’(t)|dt]dx=(b-a)∫ab|f’(x)|dx. 故得证.

解析
转载请注明原文地址:https://kaotiyun.com/show/tgt4777K
0

最新回复(0)