设f二阶可导,z=y/xf(xy),则

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问题 设f二阶可导,z=y/xf(xy),则

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答案-1/x2f(xy)+y/xf’(xy)+y2f"(xy)

解析 =-y/x2f(xy)+y2/xf’(xy),=-1/x2f(xy)-y/xf’(xy)+2y/xf’(xy)+y2f"(xy)=-1/x2f(xy)+y/xf’(xy)+y2f"(xy).
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