函数y=(x-1)2(x-2)2(-3≤x≤4)的值域是____________.

admin2021-07-02  30

问题 函数y=(x-1)2(x-2)2(-3≤x≤4)的值域是____________.

选项

答案[0,400]

解析 =2(x-1)(x-2)2+2(x-1)2(x-2)
=2(x-1)(x-2)(2x-3)


值域是[0,400]
转载请注明原文地址:https://kaotiyun.com/show/Iny4777K
0

随机试题
最新回复(0)