函数y=(x-1)2(x-2)2(-3≤x≤4)的值域是____________.

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问题 函数y=(x-1)2(x-2)2(-3≤x≤4)的值域是____________.

选项

答案[0,400]

解析 =2(x-1)(x-2)2+2(x-1)2(x-2)
=2(x-1)(x-2)(2x-3)


值域是[0,400]
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