(1)设=8,则a=________. (2)设x-(a+bcosx)sinx为x的5阶无穷小,则a=________,b=_________. (3)设当x→0时,f(x)=ln(1+t)dt~g(x)=xa(ebx-1),则a=_______,b=__

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问题 (1)设=8,则a=________.
(2)设x-(a+bcosx)sinx为x的5阶无穷小,则a=________,b=_________.
(3)设当x→0时,f(x)=ln(1+t)dt~g(x)=xa(ebx-1),则a=_______,b=_________.

选项

答案(1)ln2 (2)a=4/3,b=-1/3 (3)a=3,b=1/2

解析

再由g(x)=xa(ebx-1)~bxa+1得a=3,b=.
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