设f’(x)=arcsin(x一1)2且f(0)=0,求I=∫01f(x)dx.

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问题 设f’(x)=arcsin(x一1)2且f(0)=0,求I=∫01f(x)dx.

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答案由f(0)=0得f(x)=∫0xarcsin(t一1)2dt,则 ∫01f(x)dx=xf(x)|01一∫01xarcsin(x一1)2dx =f(1)一∫01[(x一1)+1]arcsin(x一1)2dx [*]

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