设z=f(x,y)由方程z-y-x+xez-y-x=0确定,求dz.

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问题 设z=f(x,y)由方程z-y-x+xez-y-x=0确定,求dz.

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答案对z-y-x+xez-y-x=0两边求微分,得 dz-dy-dx+ez-y-xdx+zez-y-x(dz-dy-dx)=0, 解得dz=[*]

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