设函数f(x,y)可微,又f(0,0)=0,fx’(0,0)=a,fy’(0,0)=b,且φ(t)=f(t,t2)],求φ’(0).

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问题 设函数f(x,y)可微,又f(0,0)=0,fx’(0,0)=a,fy’(0,0)=b,且φ(t)=f(t,t2)],求φ’(0).

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答案在φ(t)=f[t,f(t,t2)]中令u=t,v=f(t,t2),得φ(t)=f(u,v),[*]

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