设f(x)在(0,+∞)内二阶可导,满足f(0)=0,f"(x)<0(x>0),又设b>a>0,则a<x<b时,恒有( )

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问题 设f(x)在(0,+∞)内二阶可导,满足f(0)=0,f"(x)<0(x>0),又设b>a>0,则a<x<b时,恒有(    )

选项 A、af(x)>xf(a).
B、bf(x)>xf(b).
C、xf(x)>bf(b).
D、xf(x)>af(a).

答案B

解析
令    g(x)=xf’(x)—f(x),
则    g(0)=0,g’(x)=xf"(x)<0(x>0),
因此    g(x)<g(0)=0(x>0),
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