∫-π/4π/4dx/(1-sinx)=________.

admin2022-10-25  20

问题-π/4π/4dx/(1-sinx)=________.

选项

答案2

解析-π/4π/4dx/(1-sinx)=∫0π/4(1/(1-sinx)+1/(1+sinx))dx=∫0π/42/(1-sin2x)dx=2∫0π/4sec2xdx=2tanx|0π/4=2.
转载请注明原文地址:https://kaotiyun.com/show/mBC4777K
0

随机试题
最新回复(0)