求下列函数的极值 f(x)=(x-1)2(x+1)3

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问题 求下列函数的极值
f(x)=(x-1)2(x+1)3

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答案f’(x)=2(x-1)(x+1)3+3(x2-1)2=(x-1)(x+1)2(5x-1), f”(x)=(x+1)2(5x-1)+2(x+1)(x-1)(5x-1)+5(x+1)2(x-1) =4(x+1)(5x2-2x-1), 由f’(x)=0得稳定点x=1,-1,1/5.由于[*],故x=1/5是f(x)的极大值点,极大值为f(1/5)=3456/3125;f”=16>0,故x=1是f(x)的极小值点,极小值为f=0;f”(-1)=0,且当x<-1时,f’(x)>0,-1<x<1/5时,f’(x)>0,从而x=-1不是f(x)的极值点.

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