设则∫02f(x-1)dx=________.

admin2021-10-18  38

问题则∫02f(x-1)dx=________.

选项

答案π/4+2ln2-1

解析02f(x-1)dx=∫02f(x-1)d(x-1)=∫-11f(x)=∫-10dx/(1+x2)+∫01ln(1+x)dx=arctanx|-10++xln(1+x)|01-∫01x/(1+x)dx=π/4+ln2-∫01(1-1/1+x)dx=π/4+2ln2-1.
转载请注明原文地址:https://kaotiyun.com/show/4ty4777K
0

最新回复(0)