计算∫01dy∫0y2ycos(1-x)2dx=______.

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问题 计算∫01dy∫0y2ycos(1-x)2dx=______.

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答案[*]

解析01dy∫0y2ycos(1-x2)dx=∫01cos(1-x)2dxydy
01(1-x)cos(1-x)2dx=01cos(1-x)2d(1-x)2
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