2. 考研
  3. 设f(x，y)在[a，b]×[c，d]上连续，g(x，y)=∫0xdu∫cyf(u，v)dv，证明：g’’xy=g’’yx=f(x，y)(a＜x＜b，c＜y＜d)．

设f(x，y)在[a，b]×[c，d]上连续，g(x，y)=∫0xdu∫cyf(u，v)dv，证明：g’’xy=g’’yx=f(x，y)(a＜x＜b，c＜y＜d)．

admin2021-08-02  27
问题 设f(x，y)在[a，b]×[c，d]上连续，g(x，y)=∫0xdu∫cyf(u，v)dv，证明：g’’xy=g’’yx=f(x，y)(a＜x＜b，c＜y＜d)．
选项
答案由于 [*] 又g(x，y)=∫axdu∫cxf(u，v)=∫cydv∫ax(u，v)du，故g”xy=f(x,y)，所以g”xy=g”yx=f(x,y)．
解析
转载请注明原文地址:https://kaotiyun.com/show/IXy4777K
0

考研数学二

相关试题推荐
随机试题
最新回复(0)