设f(x)=∫01|x-y|sindy(0<x<1),求f’’(x).

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问题 设f(x)=∫01|x-y|sindy(0<x<1),求f’’(x).

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答案f(x)=∫01|x-y|sin[*]=∫0x(x-y)sin[*]+∫x1(y-x)sin[*] =x∫0xsin[*]-∫0xysin[*]+x∫1xsin[*]-∫1xysin[*] 则f’(x)=∫0xsin[*]+∫1xsin[*],f’’(x)=2sin[*]

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