∫0Rdxln(1+x2+y2)dy(R>0).

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问题0Rdxln(1+x2+y2)dy(R>0).

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答案如图8.16所示. [*] I=[*]ln(1+x2+y2)dσ[*]dθ∫0Rln(1+r2)rdr [*] =[*][R2ln(1+R2)-R2+ln(1+2)] =[*][(1+R2)ln(1+R2)-R2].

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