设z=f(x,y)满足:,f’x(x,0)=2cosx,f(0,y)=ey+1,则f(x,y)=________.

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问题 设z=f(x,y)满足:,f’x(x,0)=2cosx,f(0,y)=ey+1,则f(x,y)=________.

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答案[*]=2xy+h(x), 由f’x(x,0)=2cosx得h(x)=2cosx,即[*]=2xy+2cosx, 从而z=x2y+2sinx+g(y), 再由f(0,y)=ey+1得g(y)=ey+1,故f(x,y)=xyy+2sinx+ey+1.

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