设z=f(x,y),)由方程z-y-x+xez-y-x=0确定,求dz.

admin2021-10-18  18

问题 设z=f(x,y),)由方程z-y-x+xez-y-x=0确定,求dz.

选项

答案对z-y-x+xez-y-x=0两边求微分,得dz-dy-dx+ez-y-xdx+xez-y-x(dz-dy-dx)=0,解得dz=[1+(x-1)ez-y-x]/(1+xez-y-x)dx+dy.

解析
转载请注明原文地址:https://kaotiyun.com/show/wCy4777K
0

最新回复(0)