设z=f(x,y)由f(x+y,x-y)=x2-y2-xy确定,求dz.

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问题 设z=f(x,y)由f(x+y,x-y)=x2-y2-xy确定,求dz.

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答案令[*]代入得f(u,v)=[(u+v)2-(u-v)2-(u-v)(u+v)]/4=uv-1/4u2+1/4v2,从而z=f(x,y)=xy-1/4x2+1/4y2,由dz/dx=y-1/2x,dz/dy=x+1/2y得dz=(y-1/2x)dx+(x+1/2y)dy.

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