设求∫02f(x-1)dx.

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问题求∫02f(x-1)dx.

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答案02f(x-1)dx=∫02f(x-1)d(x-1)∫-11f(x)dx=∫-10dx/(1+x2)+∫01ln(1+x)dx=arctanx|-10+xln(1+x)|01-∫01x/(1+x)dx=π/4+ln2-∫01[1-1/(1+x)]dx=π/4+2ln2-1.

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