设D=((x,y)|a≤x≤b,c≤y≤d),若f’’xy与f’’yx在D上连续, 证明: ∫∫Df’’xy(z,y)dxdy=∫∫Df’’yx(z,y)dxdy;

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问题 设D=((x,y)|a≤x≤b,c≤y≤d),若f’’xy与f’’yx在D上连续,
证明:
∫∫Df’’xy(z,y)dxdy=∫∫Df’’yx(z,y)dxdy;

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答案[*] 同理[*] 结论成立.

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