求∫-π/2π/2[sin7x/(1+x10)+1/(1+cosx)]dx．

admin2021-10-18 52

问题求∫_-π/2^π/2[sin⁷x/(1+x¹⁰)+1/(1+cosx)]dx．

选项

答案∫_-π/2^π/2[sin⁷x/(1+x¹⁰)+1/(1+cosx)]dx=∫_-π/2^π/21/(1+cosx)-2∫₀^π/21/(1+cosx)dx=2∫₀^π/2sec²x/2d(x/2)=2tanx/2｜₀^π/2=2．

解析

转载请注明原文地址:https://kaotiyun.com/show/KRy4777K

考研数学二

相关试题推荐

随机试题

最新回复(0)