设z=f(x,y)满足:=2x,f’x(x,0)=2cosx,f(0,y)=ex+1,则f(x,y)=________.

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问题 设z=f(x,y)满足:=2x,f’x(x,0)=2cosx,f(0,y)=ex+1,则f(x,y)=________.

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答案x2y+2sinx+ey+1

解析 =2xy+h(x),
由f’(x,0)=2cosx得h(x)=2cosx,即=2xy+2cosx.
从而z=x2y+2sinx+g(y),
再由f(0,y)=ey+1得g(y)=ey+1,故f(x,y)=x2y+2sinx+ey+1.
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