2. 考研
  3. ∫01dy∫0y2ycos(1-x)2dx=_______．

∫01dy∫0y2ycos(1-x)2dx=_______．

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问题 ∫01dy∫0y2ycos(1-x)2dx=_______．
选项
答案[*]
解析 ∫01dy∫0y2ycos(1-x)2dx=∫01cos(1-x)2dxydy
=∫01(1-x)cos(1-x)2dx=∫01cos(1-x)2d(1-x)2
=∫01costdt=∫01costdt=sin1．
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考研数学三

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