设二次型f(x1,x2,x3)=x12一x22+2ax1x3+4x2x3的负惯性指数为1,则a的取值范围是_______.

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问题 设二次型f(x1,x2,x3)=x12一x22+2ax1x3+4x2x3的负惯性指数为1,则a的取值范围是_______.

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答案[-2,2]

解析 f(x1,x2,x3)=x12一x22+2ax1x3+4x2x3=x12+2ax1x3+a2x32一x22+4x2x3一a2x32
    =(x1+ax3)2一(x2—2x3)2+(4一a2)x32=y12-y22+(4一a2)y32
  若负惯性指数为1,则4一a2≥0,a∈[一2,2],故填[一2,2].
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