设二元函数z=f(x,y)满足=excosy+y,又fx(x,0)=,f(0,y)=y,则f(x,y)=______________.

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问题 设二元函数z=f(x,y)满足=excosy+y,又fx(x,0)=,f(0,y)=y,则f(x,y)=______________.

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解析

从而
再由f(0,y)=y得h(y)=y-siny.
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