曲线r=eθ在θ=π/2处的切线方程为________.

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问题 曲线r=eθ在θ=π/2处的切线方程为________.

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答案y=-x+eπ/2

解析 当θ=π/2时,x=0,y=eπ/2.dy/dx=(dy/dθ)/(dx/dθ)=(sinθ+cosθ)/(cosθ-sinθ),k=dy/dx|θ=π/2=-1,所求切线方程为y=-x+eπ/2
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