∫0π/2sinx/(sinx+cosx)dx=________.

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问题0π/2sinx/(sinx+cosx)dx=________.

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答案π/4

解析 由I=∫0π/2sinx/(sinx+cosx)dx=∫0π/2cosx/(cosx+sinx)dx得2I=∫0π/2sinx/(sinx+cosx)dx+∫0π/2cosx/(cosx+sinx)dx=∫0π/2dx=π/2,故∫0π/2sinx/(sinx+cosx)dx=π/4.
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