设f(x)在[a,b]上满足|f’’(x)|≤2,且f(x)在(a,b)内取到最小值。证明:|f’(a)|+|f’(b)|≤2(b—a).

admin2017-08-31  39

问题 设f(x)在[a,b]上满足|f’’(x)|≤2,且f(x)在(a,b)内取到最小值。证明:|f(a)|+|f(b)|≤2(b—a).

选项

答案因为f(x)在(a,b)内取到最小值,所以存在c∈(a,b),使得f(c)为f(x)在[a,b]上的最小值,从而f(c)=0. [*]

解析
转载请注明原文地址:https://kaotiyun.com/show/3Ur4777K
0

最新回复(0)