设函数f(x),g(x)满足f’(x)=g(x),g’(x)=2ex-f(x)且f(0)=0,g(0)=2,求.

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问题 设函数f(x),g(x)满足f’(x)=g(x),g’(x)=2ex-f(x)且f(0)=0,g(0)=2,求.

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答案由f’(x)=g(x)得f"(x)=g’(x)=2ex-f(x)于是有 [*] 解之得f(x)=sinx-cosx+ex,又 [*]

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