设函数y=f(x)由方程e2x+y-cos(xy)=e-1所确定,则曲线y=f(x)在点(0,1)处的法线方程为____________.

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问题 设函数y=f(x)由方程e2x+y-cos(xy)=e-1所确定,则曲线y=f(x)在点(0,1)处的法线方程为____________.

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答案x-2y+2=0

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