∫0x(x-t)2dt=________.

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问题 0x(x-t)2dt=________.

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答案由∫0xxsin(x-t)2dt=x∫0xsin(x-t)2dt[*]x∫0xsinu2du得 [*]∫0xxcsin(x-t)2dt=[*](x∫0xsinu2du)=∫0xsinu2du+xsinx2

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