设f(x)连续,且

admin2019-02-23  21

问题 设f(x)连续,且

选项

答案1

解析0xtf(x-t)dt=x0(x-u)f(u)(-du)=x∫0xf(u)du-∫0xuf(u)du,
0xarctan(x-t)2dtx0arctanu2(-du)=∫0xarctanu2du,
转载请注明原文地址:https://kaotiyun.com/show/Dz04777K
0

最新回复(0)